The figure of 14,000,000 to 1 is often quoted as being the odds
of winning the lottery. Is this the
correct odds of winning, and how is this calculated?
You need to get the correct six balls (in any order) from 49.
Thus:
chance= (6/49)(5/48)(4/47)(3/46)(2/45)(1/44)
= (6!)(43!)/(49!)
= 1/13,983,816
For those with a little less knowledge of
probability:
The probability of thing A happening and thing B happening
is found by multiplying the two probabilities. For example, if you
toss two coins, the probability of getting heads on the first
and heads on the second is
½×½=¼.
When you sit watching the balls coming out of the machine, the
probability that the first one is one of your six is 6/49. If it
is, there are now 48 balls left, and 5 of them are ones you want,
so the probability that the next ball is one of your numbers is
5/48. And so on. Hopefully this explains Neil's formula. His second
line uses factorial notation, which may be unfamiliar, but if you
multiply the fractions you should get to the answer at the
bottom.