Hello,
I found your web page by searching for "probability" - I am from
Newcastle, Australia.
I'm interested in a particular problem - just because it has
intrigued me for years.
I walk into a shop and take a lotto ticket - if I choose six
numbers following each other (ie 1,2,3,4,5,6) do I have the same
theoretical chance of them coming up as if I choose a random six
numbers that are not sequential.
If each number has an equal chance of being selected (assuming that
the painted number on the higher numbered balls does not make them
heavier, etc) then there should be as much chance of the six
sequential numbers coming up - or is there an additional
calculation to incorporate the chance of numbers selected being
sequential ?
Your mathematical assistance would be appreciated and would calm an
otherwise vexing problem.
Regards
Terry Roche
Terry,
Imagine the marking on the balls were not different numbers but
different colours. It should be completely obvious that no
particular sequence of colours will be favoured over any other. It
is the same with numbers. Just because we have defined a special
order 1,2,3,... etc. It isn't really special in any other sense
than convention. So to answer your question: the sequence
1,2,3,4,5,6 is no less or more likely than any other
sequence.
Obviously, that sequence, like any other, is unlikely to come
up!
Sean
While this is certainly true it doesn't mean to say that the
chance of getting 6 consecutive numbers = chance of not getting 6
consecutive numbers. All it means is that the chance of getting a
specific set of 6 consecutive numbers (e.g. 1-6) = chance of
getting a specific set of non-consecutive numbers. However
overall there are many more possibilities for the later, and if you
add them all up you find:
The chance of getting 6 consecutive numbers is much less than the
chance of not getting 6 consecutive numbers
Michael