How do you work out the area of an ellipse (oval)?
If you can help I will be very grateful, thank you
There are several explanations below, at very different levels. Don't be put off if you don't understand the first ones!
You just have to integrate the equation of the oval. If the
parametric equation of the oval is
x=acos(t)
y=bsin(t)
then integrate ydx from 0 to p/2 and
multiply the answer by 4 (because of symmetry). The general answer
is Area=pab where a and b are half of
the major and minor axes.
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Hopefully this diagram shows what is meant by a and b. |
The area for a circle must also satisfy the result for an
ellipse with a=b, which it clearly does. The canonical equation of
an ellipse is:
x2/a2 + y2/b2 = 1
I've always wondered why anyone would integrate, when you can find the result simply by scaling a unit circle in two directions. We know that if a shape S has area A, and we apply the linear transformation T(x,y)=(ax,by), then T(S) has area A.det(T)=abA. Applying this to a circle of unit radius, and an ellipse of semi-minor axis a and semi-major axis b, the area of the ellipse is then ab.(p×12)=pab.
Yes Dan, but generally students study matrices and
transformations after integration. ;)
Neil M
True, but you don't really need to have studied transformations to see that scaling by b in the y-direction will multiply the area by b, similarly in the x-direction.
Putting that into simpler language:
Imagine a square measuring 1 unit by 1 unit (area 1 square
unit).
Now imagine we stretch that to be a times as wide. Its area will
now be a square units.
Now imagine stretching it to be b times as high. Its area will now
be a×b=ab square units.
We can do the same thing with a unit circle: one whose radius is 1
unit, and whose area is p×1×1=p
square units.
If we stretch it to be a times as wide, and b times as high, its
area will be multiplied by a and b, so it will be pab.